Question

calculate the compound interest on rs 6000 at 10% per annum for two years

Answer 1

Heya friend,

Given that

P = ₹6,000

R = 10 % p.a.

T = 2 years

Solution

C.I. = P{(1+R/100)^ n - 1}

= 6,000{(1+10/100)^2 - 1}

= 6,000{(100+10/100)^2 - 1}

= 6,000{(110/100)^2 - 1}

= 6,000{(11/10)^2 - 1}

= 6,000{121/100 - 1}

= 6,000{121-100/100}

= 6,000 × 21/100

= ₹1,260








Thanks

With regards@

Tanisha

Answer 2

GIVEN 》

Principal = Rs 6000

Rate of interest = 10 %

No. of years = 2

TO FIND 》

compound interest

SOLUTION 》

A = P ( 1 + R/ 100)^N

= 6000 ( 1 + 10 /100 )^2

= 6000 × 11/ 10 × 11/10

= 60 × 121

= 7260

so amount = Rs 7260

C . I . = A - P

= 7260 - 6000

= 1260

so compound interest is Rs 1260