calculate the concentration of a solution in % by volume when 56g of water is mixed with 0.17l of ethanol ??
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Answered by
61
To calculate concentration by volume, first convert into volumes.
Volume of ethanol = 0.17l
Volume of water = 56g/(1g/cm³) = 56 ml = 0.056l
(taking density of water = 1g/cm³)
Total volume of solution = 0.17 + 0.056 = 0.226l
Concentration of ethanol = × 100
⇒ Concentration = × 100
⇒Concentration = 75.22%
Volume of ethanol = 0.17l
Volume of water = 56g/(1g/cm³) = 56 ml = 0.056l
(taking density of water = 1g/cm³)
Total volume of solution = 0.17 + 0.056 = 0.226l
Concentration of ethanol = × 100
⇒ Concentration = × 100
⇒Concentration = 75.22%
Answered by
16
concentration of ethanol in % = 100 * volume of ethanol / total volume of solution
= 100 * volume of Ethanol / [ volume of ethanol + volume of water ]
= 100 * 170 cc / [ 170 cc + 56 cc ] = 75.22 %
as 1 liter = 1000 cc and 1 gm of water occupies 1 cc.
= 100 * volume of Ethanol / [ volume of ethanol + volume of water ]
= 100 * 170 cc / [ 170 cc + 56 cc ] = 75.22 %
as 1 liter = 1000 cc and 1 gm of water occupies 1 cc.
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