Calculate the concentration of H+ ion in the following Acetic Acid solution pKa=4.76
[CH₃COOH]/[CH₃COO-]=0.5
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Explanation:
pH = – log[4 × 10–3 ]
= – {log[4] + log[10–3 ]}
= – {(0.6) + (– 3.0)}
= – {– 2.4} = 2.4
Therefore, the pH is 2.4 and it is acidic.
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