Calculate the concentration of pcl3 at equilibrium if 1 mole of pcl5 is taken in 10 l solution
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Answer:
PCl
5
⇋PCl
3
+Cl
2
Initial conc.(M) 0.1 0 0
At eq. 0.1−x x x
The expression for the equilibrium constant is:
K
c
=
[PCl
5
]
[PCl
3
][Cl
2
]
=
0.1−x
x×x
=13.7
Hence, x=0.0993
Total number of moles =n=10(0.1+x)=10(0.1+0.0993)=1.993
P=
V
nRT
=
10
1.993×0.0821×546
P=8.93
100P=893
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