Question

Calculate the coulomb force acting on a proton inside an alpha particle.

Answer 1

Explanation:

Given :

Separation between alpha particle and proton is , r=5.12\times 10^{-15}\ mr=5.12×10−15 m .

To find :

Force between them .

Solution :

Charge on proton , q_p=1.6\times 10^{-19}\ Cqp=1.6×10−19 C .

Now , we know charge on  alpha particle is twice the charge on proton .

Therefore , q_\alpha=2\times 1.6\times 10^{-19}\ Cqα=2×1.6×10−19 C .

We know , force is given by :

F=\dfrac{kq_p\ q_\alpha}{r^2}F=r2kqp qα

Here , k=9\times 10^9\ N\ m^2\ C^{-2}k=9×109 N m2 C−2

Putting all values in above equation .

We get :

\begin{gathered}F=\dfrac{9 \times 10^9\times 1.6\times 10^{-19} \times 2\times 1.6\times 10^{-19}}{(5.12\times 10^{-15})^2}\\\\F=17.58\ N\end{gathered}F=(5.12×10−15)29×109×1.6×10−19×2×1.6×10−19F=17.58 N

Therefore , coulomb force between alpha particle and proton is 17.58 N .

Answer 2

Answer:

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Explanation:

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