Question

Calculate the coulombs force between two protons separated by a distance of 20 cm

Answer 1

F = k [q/r]²
= 9 × 10^9 × [(1.6 × 10^-19) / (0.2 m)]²
= 5.76 × 10^-27 N

∴ Force between protons is 5.76 × 10^-27 N

Answer 2

Heya.......!!!!

To calculate the Force between two protons we will apply the simple formulae :

F = K× q1× q2 / r^2

Here => q1 = q2 = 1.6 × 10^-19 C .
distance ( r ) = 20cm = 0.2 m .
K = 9 × 10^9

substituting the values in formulae we get ,

=> F = [ 9 ×10^9 × ( 1.6 ×10^-19 )^2 ] ÷ 0.2^2

➡=>> F = 5.76 × 10^-27 N is the force between two protons.

Hope It Helps You ^_^