Question

Calculate the current flowing through the circuit shown below.
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Answer 1

Answer:

0.13 Ampere

Explanation:

The given circuit is a combination of a 30Ω  resistor in parallel with two 30Ω  resistors in series.

therefore ,

         1/R(eq) = 1/30 + 1/(30 + 30)

=> R(eq) = (60 x 30)/(60 + 30 + 30)

=> R(eq) = 1800/120

=> R(eq) = 15Ω

V = iR(eq)         -  from ohm's law

i = V/R(eq) = 2/ 15

=> i = 0.13 A  

I may be wrong with the values because the picture is not clear , but I hope the process is clear to you

Answer 2

TOTAL R = 30 Ω +30 Ω + 30 Ω

               = 90 Ω

we know

V = IR

- 2 = I × 90

∴ I = 90 / -2

  I = - 45 A

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