Calculate the current strength and number of moles of electron required to produce 2.369×10-3 kg of cu from cuso4 solution in one hour. (molar mass of cu is 63.59/mol)
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The amount of current required will be 2 Ampere.
Explanation :
Let the current passed is I
=> I coulomb of charge is passed in 1 sec
=> charge passed in 1 hour = I x 60 x 60 = 3600I C
The reaction of copper is given by,
Cu²⁺ + 2e⁻ = Cu
From the reaction it is clear that 2 moles of electron are required to form 1 mole of copper
=> 2 x 96485 C of charge = 63.59 g
=> 3600I C of charge = 63.59 x 3600I/(2x96485) = 2.369 g
=> I = (2.369 x 2 x 96485)/(3600 x 63.59)
=> I = 2 A
Hence The amount of current required will be 2 Ampere.
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