Question

Calculate the current through each resistance in the circuit given below.
Also redraw the diagram and show the flow of current using arrows.
212
222
4 92
RA
422
6 V​

Answer 1

Answer:

Post the picture of the circuit. Won't be able to calculate without it.

✌

Answer 2

Show the flow of current in the diagram.

Explanation:

Given that,

Resistance $R_{1}=2\ \Omega$

Resistance $R_{2}=4\ \Omega$

Resistance $R_{3}=4\ \Omega$

Resistance $R_{4}=2\ \Omega$

R₂ and R₃ are connected in parallel

We need to calculate the resultant resistance

Using formula of parallel

$\dfrac{1}{R}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}$

Put the value into the formula

$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{4}$

$R=2\ \Omega$

R₁, R and R₄ are connected in series

We need to calculate the resultant resistance

Using formula of series

$R'=R+R_{1}+R_{4}$

Put the value into the formula

$R'=2+2+2$

$R'=6\ \Omega$

We need to calculate the current

Using ohm's law

$V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{6}{6}$

$I=1\ A$

The current is equally distributed in series resistance and the current is equally divided  in parallel resistance.

Hence, Show the flow of current in the diagram.

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Topic : electricity

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