Chemistry, asked by hudsonmat15, 11 months ago

calculate the de broglie wavelength of a particle whose momentum is 66.26 ×10-28kgms-1

Answers

Answered by puru83

3

h=6.626×10^-34

so... lambda=h/p

Attachments:

Answered by ezhilnikil4488

2

Answer:

wave length = h/p

wavelength=10-7|

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