Question

Calculate the mass of silver that contain same number of atoms as are the present in 5.6g of iron

Answer 1

no of atoms of Fe = no of atoms of Ag

avogadro no x (mass of Fe) / (atomic mass of Fe) = avogadro no x (mass of Ag) / (atomic mass of Ag)

6.02 x 1023 x 5.6 / 56 =6.02 x 1023 x mass of Ag / 108

mass of Ag = 108 x 5,6 / 56

mass of Ag = 10.8 g

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