Calculate the mass of silver that contain same number of atoms as are the present in 5.6g of iron
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no of atoms of Fe = no of atoms of Ag
avogadro no x (mass of Fe) / (atomic mass of Fe) = avogadro no x (mass of Ag) / (atomic mass of Ag)
6.02 x 1023 x 5.6 / 56 =6.02 x 1023 x mass of Ag / 108
mass of Ag = 108 x 5,6 / 56
mass of Ag = 10.8 g
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avogadro no x (mass of Fe) / (atomic mass of Fe) = avogadro no x (mass of Ag) / (atomic mass of Ag)
6.02 x 1023 x 5.6 / 56 =6.02 x 1023 x mass of Ag / 108
mass of Ag = 108 x 5,6 / 56
mass of Ag = 10.8 g
Hope it's help you. Please mark me in the brain list
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