calculate the de broglie wavelength of an electron
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Explanation:
If we divide the Planck constant by the momentum, we will obtain the de Broglie wavelength: h/p = 6.6261*10-34 / 2.7309245*10-24 = 2.426*10-10 m . Choosing proper units, we can say that the de Broglie wavelength of this electron is equal to 0.24 nm.
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