Question

Calculate the de broglie wavelength of an electron travelling at 1 of the speed of light

Answer 1

as we know the de brogile wavelength equation as lamda = plancks constant/momentum

lambda=h/m*v

velocity of light is 3*10^8m/s^2

10% of speed of light= 10/100 * 3*10^8 = 0.3*10^8

lambda= 6.636 * 10^-34 / 9.11 * 10^-31 *(.3 * 10^8)

we get lambda= 2.428 * 10^-11 m

the de brogile wavelength is 2.428 * 10^-11 m