Question

Calculate the electric field that an electron experiences in the hydrogen atom.

Answer 1

Based on the problem, we know:

∙

r

=

5.29

×

10

−

11

m

∙ r=5.29×10−11 m

∙

Q

p

=

1.602

×

10

−

19

C

∙ Qp=1.602×10−19 C

The equation for the magnitude of the electric field caused by the proton is:

E

=

k

Q

r

2

E=kQr2

The value of the electrostatic constant is equal to:

k

=

9.0

×

10

9

N

m

2

/

C

2

k=9.0×109 Nm2/C2

Substitute the given and the known values.

E

=

9.0

×

10

9

N

m

2

/

C

2

1.602

×

10

−

19

C

(

5.29

×

10

−

11

m

)

2

E=9.0×109 Nm2/C21.602×10−19 C(5.29×10−11 m)2

E

=

5.15

×

10

11

N

/

C

E=5.15×1011 N/C