Question

Calculate the density of diamond from it has face centered cubic structure with two atoms per lattice points and a unit cell of edge length 3.569

Answer 1

d=ZMN0a3Here,  Z=2×4=8N0=6.022×1023a=3.569 A = 3.569×10−8 cmM=12 gTherefore, d=8×126.022×1023×(3.569×10−8)3=9627.3766=3.506 g/cm3

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Answer 2

Hello dear,

● Answer -
d = 3504 kg/m^3

● Explaination -
# Given -
Z = 2×4 = 8 atoms/cell
M = 12 g/mol = 12×10^-3 kg/mol
N0 = 6.022×10^23 atoms
a = 3.569 A° = 3.57×10^-10 m

# Solution -
Density of diamond crystal can be calculated by -
d = Z.M / N0.a^3
d = (8 × 12×10^-3) / (6.022×10^23 × 3.67^3 × 10^-30)
d = 3504 kg/m^3
d = 3.5 g/cm^3

Hence, density of diamond is 3500 kg/m^3.

Hope this helped you...

Answer 3

Hello dear,

● Answer -

d = 3504 kg/m^3

● Explaination -

# Given -

Z = 2×4 = 8 atoms/cell

M = 12 g/mol = 12×10^-3 kg/mol

N0 = 6.022×10^23 atoms

a = 3.569 A° = 3.57×10^-10 m

# Solution -

Density of diamond crystal can be calculated by -

d = Z.M / N0.a^3

d = (8 × 12×10^-3) / (6.022×10^23 × 3.67^3 × 10^-30)

d = 3504 kg/m^3

d = 3.5 g/cm^3

Hence, density of diamond is 3500 kg/m^3.

Hope this helped you...