Calculate the density of diamond from it has face centered cubic structure with two atoms per lattice points and a unit cell of edge length 3.569
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d=ZMN/a^3
Here, Z = 2×4=8
N0 = 6.022×10^23
a=3.569 A = 3.569×10^−8 cm
M=12 g
Therefore, d=8×12/6.022×10^23×(3.569×10^−8)^3
=96/27.3766
=3.506 g/cm3
Here, Z = 2×4=8
N0 = 6.022×10^23
a=3.569 A = 3.569×10^−8 cm
M=12 g
Therefore, d=8×12/6.022×10^23×(3.569×10^−8)^3
=96/27.3766
=3.506 g/cm3
rIshavQ:
centimeter cube is the unit.
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