Question

Calculate the density of paraffin oil, if glass
capillary of diameter 0.25 mm dipped in paraffin
oil of the surface tension 0.0245 N/m rises a
height of 4 cm.(angle of contact of paraffin oil
with glass is 28° and g = 9.8m/second squere)​

Answer 1

Answer:

DENSITY ( p ) = 897 kg / m³

[ For Paraffin Oil ]

Explanation:

★ FLUID MECHANICS ★

★ GIVEN ; FOR

_____________ [ GLASS CAPILLARY] ___________

» Diameter of Glass Capillary ( d ) = 0.25 mm ≈ 2.5 × 10-⁴ m

» Surface Tension ( T ) = 0.025 N / m

» Gravitational acceleration ( g ) = 9.8 m/s²

____________" WHEN GLASS CAPILLARY DIPPED IN PARAFFIN OIL " ___________

: Following changes occur :::: ----

★ Angle made by Capillary with PARAFFIN oil = Cos ∅ →{ ∅ = 28° } ←

★ Surface Tension rises by a HIEGHT ( h ) = 4cm

★ Density of PARAFFIN oil ( p ) = ???

______ [ By Using FORMULA ] ______

$h \: = \frac{2 \: \times \: t \: \times \: \cos(t) }{r \: \times p \times g \: }$

★ p = ( 2 × T × Cos ∅ ) / r × h × g

★ p = ( 2 × 0.025 × Cos 28° ) / ( 1.25 × 10-⁴ × 4 × 10-² × 9.8 )

» p = ( 0.05 × 0.88 ) / 5 × 9.8 × 10^-6

» p = 0.044 / 49 × 10^-6

» p = 89.7 × 10^-5 × 10^6

★ » p = 897 Kg / m³ « ★

_________________________________________

ANSWER :- Density Of Paraffin Oil after insertion of Glass Cappilary is :-

♣ p = 897 kg / m³

Answer 2

♋♋YOUR ANSWERS♍♍

✍ 897 kg/m³

════════════════════

EXPLANATION —

$h = \frac{2Tcos Q }{prg } \\ \\ p \: = \frac{2Tcos Q}{rgh}$

Here given

》Surface Tension T= 0.025 N/m

》radius of capillary r= 2.5/2 *10¯⁴

》gravity g=9.8 m/s²

》angle made by capillary and Paraffin oil Q= 28°

》rising of hight of Paraffin h= 4 cm

To find -

density of Paraffin (p) = ?

putting in the formula

$p \: = \frac{2 \times 0.025 \times \cos(28) }{1.25 \times {10}^{ - 4} \times 4 \times {10}^{ - 2} \times9.8 }$

on solving

p = 897 kg/m³

╒══════════════════════╕

♌ ‌ ‌‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ Thanks‌ ,hope you like it !!‌ ‌ ‌‌ ‌♌

╘══════════════════════╛