Calculate the details broglie wavelength of an electron of energy 400ev
Given, Planck constant = 6.6 x 10^-34 js. Mass of electron = 9.1 X 10^-31kg.
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Given that,
♣mass of an electron = 9.1x10 -31 kg
♣ kinetic energy = 3.0x10 -25 J
♣ h=6.6x10 -34 Js
By using de- Broglie equation :
wavelength = h/mv = h/ p ,where h = Planck's constant, p= momentum
as P= √2Em , by subtituting the value of p we get,
wavelength = h / √2Em (E= kinectic energy )
wavelength = 6.6 x 10-34/√2 x 3.0 x 10-25 x 9.1 x 10 -31 = 6.6 x 10 -34/√54.6 x 10 - 56
= 6.6 x 10 -34/ 7.4 x 10 - 28
= 0.89 x 10 -6 m
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