calculate the diameter of oxygen atom assuming that occupy is half of the volume occupied by water molecule
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Answer:
The density of water is approximately 1g/ml.
Thus, 1g of water occupy volume = 1 ml
The molar mass of water = 18 g/mol
Number of moles of water in 1g =
18
1
moles = 0.055 moles H
2
O
Now 18 g water contain = 6.022 × 10
23
moleculesH
2
O
Thus 1 g water will have =
18
6.022×10
23
molecules H
2
O = 0.334 × 10
23
molecules H
2
O
This shows that
0.334 ×10
23
molecules H
2
O will occupy volume = 1 ml
Therefore volume occupied by 1 H
2
O molecule =
0.334×10
23
1
=2.99 × 10
−23
ml
Thus volume occupied by 1 H
2
O mlecule is 2.99 × 10
−23
ml.
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