calculate the difference between the compound interest and the simple interest on 12000 at 9% per annum in 2 years.
Answers
Answer:
Step-by-step explanation:
P= 12000 Rs
R=9%
T=2 years
A=P(1+r/100)²
=12000(1+9/100)²
=12000(109/100)²
=12000 x 109 x 109/10000
=12 x 109 x 109 /10
=142572/10
=14257.2
CI = A-P
=14257.2-120000
=2257.2
SI=P x R x T/100
=12000 x 9 x 2/100
=120 x 9 x 2
=2160
CI-SI=2257.2-2160
=97.2
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Answer:
Hi mate, here is your answer :)
First we will calculate compound interest
=> Amount = pricip. X ( 1 + R / 100 ) to the power time .
=> prin.= 12000
=> Rate = 9
=> Time= 2 years
SO LET'S BEGIN WITH OUR CALCULATION
=> A = 12000 X ( 1 + 9 / 100) TO the power 2.
=> A = 12000 X ( 109 / 100 ) TO the power 2
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ROUGH PLACE (WHERE YOU CAN CALCULATE )
The sq.of 109 is = 11,881
The sq.of 100 is = 10000
[Note : we are doing squares of the numbers because their power is 2]
ROUGH PLACE END .......
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=> A = 12000 X 11,881 / 10000
=> A = 1,425.72
OUR TASK 1 COMPLETED THAT WE GOT OUR AMOUNT= 1,425.72
Lets go to Task 2
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OUR TASK 2 BEGINS ,
TASK 2 : We have to find compound interest .
C. I = amou. - Prin.
prin.= 12000
am.= 1425.72
=> CI = 12000 - 1425.72
=> CI = 10,574.28
OUR TASK 2 COMPLETED WE GOT COMPOUND INTEREST = 10,574.72.
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TASK 3 : Find simple interest
S.I = P X R X T / 100
P = 12000
R = 9
T = 2
=> S.I = 12000 X 9 X 2 / 100
=> S.I = 2,160
TASK 3 COMPLETED WE GOT THAT SIMPLE INTEREST IS 2,160
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TASK 4 BEGINS : FIND DIFFERENCE BETWEEN SIMPLE AND COMPOUND INTEREST
=> C.I - S.I
=> 10,574.28 - 2,160
=> 8414.28
WE ARE AT THE LAST AND WE GOT OUR ANSWER ....
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THANKS
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