Physics, asked by rumaanahashmi4345, 10 months ago

Calculate the difference in the temperature between the water at the top and bottom of a water fall 200m high. Specific heat of water is 4200J kg⁻¹ °C⁻¹.

Answers

Answered by gadakhsanket
93

Hey dear,

◆ Answer -

∆T = 0.4667 ℃

◆ Explanation -

Consider

m = mass of water

g = gravitational acceleration

h = height of waterfall

c = specific heat of water

∆T = change in temperature

When water falls from a height, its potential energy is converted to heat energy.

mgh = mc∆T

gh = c∆T

∆T = gh / c

∆T = 9.8 × 200 / 4200

∆T = 0.4667 ℃

Hence, temperature difference between water at top & that at bottom is 0.4667 ℃.

Hope this helped. Thanks for asking..

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