Question

Calculate the difference in wavelength for 2nd line of balmer series and 1st line of paschen series for hydrogen?

please answer​
it's urgent.....

please help me to know the answer..

Answer 1

Hello friend.

What is the ratio of wave number of second line Balmer series and second line of paschen series? The wavelength of the second Balmer line in Hydrogen spectrum is 600 nm.

For Paschen Series,

n₂ = Infinity , n₁ = 3

∴

⇒ 1/λ = R(1/9 - 1/Infinity)

λ = 1/R(0.11)

⇒ λ = 8199 × 10⁻¹⁰ m.

For Li²⁺, λ = 8199 × 10⁻¹⁰ × 3² m. = 73791 × 10⁻¹⁰ m.

∴ Difference in Wave number = 1/59032.8 × 10⁻¹⁰ - 1/73791 × 10⁻¹⁰

= 10¹⁰ (0.00001693973 - 0.00001355178)

= 10¹⁰(0.00000338795)

= 33879.5 m⁻¹

hope it's helpful for you..

❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️