calculate the dimensions of force and impulse taking velocity, density and frequency as basic quantities.
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Let we denote velocity=v, density=d, frequency=f
We have Force=[MLT-2]
Let
MLT-2=vadbfc
》MLT-2=[LT-1]a[ML-3]b[T-1]c
》MLT-2=MbLa-3bT-a-c
On comparing the exponents of both sides
》b=1____________(1)
》a-3b=1_________(2)
》a=4
》-a-c=-2________(3)
》c=-2
Hence dimension of force is
[F]=v4d f-2
We have Force=[MLT-2]
Let
MLT-2=vadbfc
》MLT-2=[LT-1]a[ML-3]b[T-1]c
》MLT-2=MbLa-3bT-a-c
On comparing the exponents of both sides
》b=1____________(1)
》a-3b=1_________(2)
》a=4
》-a-c=-2________(3)
》c=-2
Hence dimension of force is
[F]=v4d f-2
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