Question

calculate the distance and acceleration of the body moving with 5m/s^2 which comes to rest after travelling for 6 seconds

Answer 1

Answer:

actually you should give 5 m/s instead of 5 m/s²

distance (s)= 15

acceleration (a)=-0.83333 or -5/6

Explanation:

Given

intial velocity, u = 5m

final velocity,v =O

time,t= 6seconds

distance travelled,s=?

acceleration,a=?

from the first equation of motion,

v= u+ at

0=u + a×t

u=-at

-5/6= a

a= -0.8333

here negative sign indicates body is decelerating

from the equation,

v²-u²=2as

0²-5²= 2×(-5/6)×s

-25 = (-10/6)×s

(-25×6) /-10 = s

s = 15