Question

calculate the distance and displacement if a body moving around a square Park of side 40 metre in 2 minutes 20 seconds if he completes one round in 40 seconds​

Answer 1

Answer:

each side =10m

2min and 20sec= 140 sec

distance = 140 ×1m

= 140m

displacement(diagonal bd )=root of 10 + 10

= root 20

Answer 2

Answer:

Explanation:

Side of the square park = 40m

Thus, perimeter of the square park = 4 x side

= 4x40m

= 160m

According to question -

Time take to complete 1 round = 40s

Total time taken to cover x distance = 2 min 20 sec

= 140 sec

Therefore, no. of rounds covered = 140/40

= 3.5 rounds

No. of rounds = 3.5 rounds

Distance covered in 1 round = 160m

Therefore, total distance covered = 3.5 x 160 m

560 m

Displacement = $10 \sqrt{22}$ ( I have attached the solution)

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