Question

Calculate the distance from the surface of the earth at which the acceleration due to gravity is the same below and above the surface of the earth.

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Answer 1

Answer:

The answer is in the attachment above.

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Answer 2

Explanation:

$\Huge\underline{\underline{\sf ANSWER}}\\ HeLlO \: ShIvAm \: BrO........ \\ \\ We \: know \: that = > \\ g' = \frac{g}{ {(1 + \frac{h}{R} )}^{2} } \\ \\ with \: depth.. \\ g'' = g(1 + \frac{d}{R} ) \\ \\ now \: h < < r \\ g' = g {(1 + \frac{h}{R} )}^{ (- 2)} \\ \\ by \: Binomial \: Theorem---> \\ g' = g {(1 - \frac{2h}{R} )}^{ (1)} \\ \\ now \: g' = g'' \\ \\ g(1 - \frac{2h}{R} ) = g(1 - \frac{d}{r} ) \\ (g )\: and \: ( - 1) \: will \: get \: canceled \: out... \\ \frac{2h}{R} = \frac{d}{R} \\ 2h = d \\ h = \frac{d}{2}$