Calculate the distance travelled by a body before coming to rest if it is moving with a velocity of 20 metre per second given coefficient of friction between body and ground is 0.5
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As there is no other force other than frictional force action on the body, we can assume that friction is the only force action which is=0.5N
Lets assume mass of body as 1kg
F=ma
-0.5=1a
a=-0.5m/s²
therefore, putting these values in equation of motion v²=u²+2as,
0²=20²+2×-0.5 s
0²=400-1s
-400=-1s
s=400m.
therefore distance is 400m.
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Lets assume mass of body as 1kg
F=ma
-0.5=1a
a=-0.5m/s²
therefore, putting these values in equation of motion v²=u²+2as,
0²=20²+2×-0.5 s
0²=400-1s
-400=-1s
s=400m.
therefore distance is 400m.
pls mark as brainliest.
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S = u^2 / (2 μg)
= 20^2 / (2 * 0.5 * 10)
= 40 m
Distance travelled is 40 m
= 20^2 / (2 * 0.5 * 10)
= 40 m
Distance travelled is 40 m
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