calculate the distance travelled by a freely falling body during 3rd second of motion?
Answers
Answered by
5
s=u+a/2(2n-1)
s=0+g/2(6-1)
s=5*5
25 m
s=0+g/2(6-1)
s=5*5
25 m
jithinjayakumapcz6q4:
bro can elaborate the steps plzz
the distance coverd in nth second is calculated by formula u+a/2(2n-1)
since body is free falling initial velocity is 0
and a frree falling body exerience acceleration =+g
and n= the second in which distance is to be calculated i.e. 3
bro so we can also use the equation ut+1/2gt^2
noo
why bro
it will tell u the distnce covered in n secs not in nth secs
in nth sec means the sec between n and n+1 sec example 3rd and 4 th sec
Similar questions
English,
7 months ago
Hindi,
7 months ago
Political Science,
1 year ago
Environmental Sciences,
1 year ago
Math,
1 year ago