Question

Calculate the drift velocity of the free electrons in a copper wire of cross sectional area 1.0mm^2 when the current flowing through the wire is 2.0A (Number of free electrons in copper is 1×10^29 m^-3).​

Answer 1

Answer:

i=neAV

d

n=

63.5×10

−3

6×10

23

×9000

=8.5×10

28

m

−3

Hence vd=

neA

i

=

8.2×10

28

×1.602×10

19

×10

−3

1

=7.4×10

−5

m/s

0.07mm/s