Question

Calculate the e.m.f. of the following cell at 298 K,
Fe | Fe2+ (0.1M) || Ag+ (0.1 M) | Ag
Given: E Fe2+ | Fe = -0.44 V
and E® Agt | Ag = 0.80 ​

Answer 1

Answer:

1.24 V is the correct answer of the question

Emf = 0.80 - ( - 0.44) V

= 1.24 V

Answer 2

Explanation:

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