Question

calculate the effective resistance between P and Q
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Answer 1

Answer:

R1=5 ohm

R2=5ohm

R3=6ohm

R4=4ohm

R' = R1+R2

=5+5

=10ohm

R" = R3+R4

= 6+4

=10ohm

1/Rpq=1/R' + 1/R"

=1/10 +1/10

= 2/10

Rpq=10/2

=5ohm resistance

Answer 2

Effective Resistance ---

In series --- r1+r2+r3

In parallel---

In parallel----

$\frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3}$

so in case of this question

5 ohm resistors are In series

so,effective resistance

r1+r2 = ( 5 + 5)ohm = 10ohm

now resistors 6 ohm and 4 ohm are in series so

effective Resistance

(6+4)ohm =10ohm

now these two effective Resistance are in parallel

so effective Resistance

above formula

$\frac{1}{10} + \frac{1}{10}$

so R = 1/5 ohm

i.e, 5ohm is net resistance.

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