calculate the effective resistance between the points A and B in the network shown in the figure...
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Clearly , The resistance of 3 Ω and 2 Ω are connected in series combination
Thus ,
R = 3 + 2
R = 5 ohm
Also , the resistance of 3 Ω and 2 Ω are connected in series combination
Thus ,
R' = 5 ohm
Now , 1 Ω form a parrallel combination with R and R'
1/R" = 1/1 + 1/5 + 1/5
1/R" = 1 + 2/5
1/R" = 7/5
R" = 5/7 ohm
Hence , the equivalent resistance is 5/7 ohm
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