Question

Calculate the effective resistance of the total circuit​

Answer 1

Explanation:

15/11 ohm is effective resistance

Answer 2

In the given figure 1 ohm and 2 ohms are connected in series combination.

we know that,

» The combined resistance of any number of resistance connected in series is equal to the sum of the individual resistances. i.e.,

R = R₁ + R₂

By substituting the values in the formula,

$\dashrightarrow \sf R_{s} = R_{1} + R_{2}$

$\dashrightarrow \sf R_{s} = 1 + 2$

$\dashrightarrow \sf R_{s} = 3 \: ohms$

Now, 3 ohms resistor and 2.5 ohms resistor are connected in parallel combination,

We know that,

The reciprocal of the combined resistance of a number of resistance connected in parallel is equal to the sum of the reciprocal of all the individual resistances. .i.e.,

1/R = 1/R₁ + 1/R₂

By substituting the values in the formula,

$\dashrightarrow \sf \dfrac{1}{R_{eq}} = \dfrac{1}{R_{1}} + \dfrac{1}{ R_2}$

$\dashrightarrow \sf \dfrac{1}{R_{eq}} = \dfrac{1}{3} + \dfrac{1}{ 2.5}$

$\dashrightarrow \sf \dfrac{1}{R_{eq}} = \dfrac{2.5 + 3}{3 \times 2.5}$

$\dashrightarrow \sf \dfrac{1}{R_{eq}} = \dfrac{5.5}{7.5}$

$\dashrightarrow \sf R_{eq} = \dfrac{7.5}{5.5}$

$\dashrightarrow \sf R_{eq} = 1.3 \: ohms$

Thus, the effective resistance of the total circuit is 1.3 ohms.