Question

calculate the efficiency of a 0.5m^2 solar panel producing 20 W. assume that the power input is 500W. (please give the answer in percentage)

Answer 1

Given:

A solar panel producing 20 W power on consuming 500 W by solar radiation. Area of solar panel is 0.5 m².

To Find:

What is efficiency of solar panel?

Solution:

Area of solar panel = 0.5 m²

Input power$\mathbf{ =E_{in}= 500 \ W}$

Output power$\mathbf{ =E_{out}= 500 \ W}$

We know that efficiency of any machine or device is ratio of output energy to input energy, means:

$\mathbf{Efficeincy=\eta =\dfrac{E_{out}}{E_{in}}\times 100}$

On putting respective value in above equation:

$\mathbf{Efficeincy=\eta =\dfrac{20}{500}\times 100}$

$\mathbf{Efficeincy=\eta =\dfrac{20}{5}}$

Efficiency = η = 4 %

Means efficiency of solar panel is 4%.

Answer 2

Answer:

Given:

A solar panel producing 20 W power on consuming 500 W by solar radiation. Area of solar panel is 0.5 m².

To Find:

What is efficiency of solar panel?

Solution:

Area of solar panel = 0.5 m²

Input power

$\mathbf{ =E_{in}= 500 \ W}$

Output power

$\mathbf{ =E_{out}= 500 \ W}$

We know that efficiency of any machine or device is ratio of output energy to input energy, means:

$\mathbf{Efficeincy=\eta =\dfrac{E_{out}}{E_{in}}\times 100}$

On putting respective value in above equation:

$\mathbf{Efficeincy=\eta =\dfrac{20}{500}\times 100}$

$\mathbf{Efficeincy=\eta =\dfrac{20}{5}}$

Efficiency = η = 4 %

Means efficiency of solar panel is 4%.