Question

Calculate the efficiency of a heat engine working between 273 K and 373 K​

Answer 1

ANSWER: Efficiency of heat engine is 26%

The efficiency of the cycle is given as η = 1−T2/T1

I.e η = 1 - 273/373

η = 0.26

η = 26%

Answer 2

Answer:

The efficiency of a heat engine working between 273K and 373K is 0.268

Explanation:

Given, Heat engine is working in between 273 K and 373 K

TH ( temperature of source) = 373 K

TL ( temperature of sink ) = 273K

The Efficiency of heat energy:

η = 1 - $\frac{TL}{TH}$

  = 1 - $\frac{273}{373}$

  = $\frac{373-273}{373}$

   = $\frac{100}{373}$ = 0.268

Hence, The efficiency of a heat engine is 0.268.