Question

calculate the effort applied in the upward direction in case of single movable Pulley which lifts a bucket of water of 30 kgf and is efficiency of given pulley system is 60%.​

Answer 1

Answer:

25kgf

Explanation:

Efficiency = Work done by Load / Work done by Effort.

Answer 2

Given: A single movable pulley lifts a bucket of water of 30 kgf and the efficiency of the given pulley system is 60%.

To find: The effort applied in the upward direction.

Solution:

• A pulley is a simple machine, a wheel-like object with a groove around it through which a string passes. The effort applied on the string through a pulley helps to lift heavy objects.
• In a movable pulley, the effort is to be applied in the upward direction.
• The efficiency of a single movable pulley is given as,

        $\eta = \frac{L}{E} * 100$

• Here, η is the efficiency, L is the load lifted by the pulley and E is the effort applied to lift the load.

        $60 = \frac{30kgf}{E} * 100$

        $E = 50 kgf$

Therefore, the effort applied in the upward direction is 50 kgf.