Question

calculate the electric current passing through the circuit when the key is closed,V=10v,5ohm,10ohm,15ohm are connected
in series​

Answer 1

Answer:

.3333 ampere

Explanation:

the resistors are connected in series therefore the equivalent resistance = 15+10+5=30 ohm

potential difference (v) = 10 volt

then

we know that

V = I × R

I = V / R

then I = 10 / 30

I = 0.3333 ampere

MARK IT AS BRAINLIEST

Answer 2

The electric current passing through the circuit when the key is closed,V=10v,5ohm,10ohm,15ohm are connected  in series​: 1/3 Ampere

Explanation:

Electric current

It is the rate of following charge through a conductor .

Its formula is I=q/t

Its unit is : Ampere

Ohm's law

It states that at constant temperature , current flowing through a wire is directly proportional to potential difference applied that is :

V=IR

Now , in above asked question:

R1=5 ohm

R2=10ohm

R3=15 ohm

V=10Volts

They(resistances ) all are connected in series therefore :

Total resistance = R1 +R2+R3=5 +10+15=30ohm

To calculate current in circuit , we have

V=IR

10=I.30

or, I=10/30=1/3Ampere =.3 A