Question

calculate the electric field due to a charge of -8*10^-8C at a distance of 5cm ​

Answer 1

Answer:

The electric field is −287680 N/m².

Explanation:

Given that,

Charge $q=-8\times10^{-8}\ C$

Distance = 5 cm

We need to calculate the electric field

Using formula of electric field

$E= \dfrac{kq}{r^2}$

Where, q = charge

r = distance

k = constant

Put the value into the formula

$E=\dfrac{8.99\times10^{9}\times(-8\times10^{-8})}{(5\times10^{-2})^2}$

$E=−287680\ N/C$

Hence, The electric field is −287680 N/C.

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Topic : Electric field

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