Calculate the electric field due to an electric dipole of length 10cm having charge of one micro coulomb at an equatorial point 12cm from the center of the diole
Answers
Therefore the Electric field due to an electric dipole is 4.1 × 10^5 N/C.
Given : An electric dipole of length 10cm having charge of one micro coulomb at an equatorial point 12cm from the centre of the dipole.
To find : The electric field due to the electric dipole.
solution : The electric field due to an electric dipole is given by, E = KP/(r² + a²)³/²
where P = q2a = 10^-6 C × 10 × 10^-2 m = 10^-7 Cm
r = 12 cm = 0.12 m and a = 5cm = 0.05 m
The electric field, E = (9 × 10^9 × 10^-7)/[(0.12)² + (0.05)²]³/²
= (900)/[0.0144 + 0.0025]³/²
= 900/(0.0169)³/²
= 900/(0.13)³
= 900/0.002197
= 409,649.522
≈ 4.1 × 10^5 N/C
Therefore the Electric field due to an electric dipole is 4.1 × 10^5 N/C.
Answer:
Therefore the Electric field due to an electric dipole is 4.1 × 10^5 N/C.
Given :
An electric dipole of length 10cm having charge of one micro coulomb at an equatorial point 12cm from the centre of the dipole.
To find :
The electric field due to the electric dipole.
solution :
The electric field due to an electric dipole is given by, E = KP/(r² + a²)³/²
where P = q2a = 10^-6 C × 10 × 10^-2 m = 10^-7 Cm
r = 12 cm = 0.12 m and a = 5cm = 0.05 m
The electric field, E = (9 × 10^9 × 10^-7)/[(0.12)² + (0.05)²]³/²
= (900)/[0.0144 + 0.0025]³/²
= 900/(0.0169)³/²
= 900/(0.13)³
= 900/0.002197
= 409,649.522
≈ 4.1 × 10^5 N/C