Question

Calculate the electric field in a copper wire of cross-sectional area 2.0 mm^2 carrying a current of 1 A. The conductivity of copper is 6.25*10^7 S/m. 

Answer 1

8 mV/m is the electric field.

Explanation:

Given that,

A = 2 * 10^-6 m^2

i = 1 A

б = 6.25 * 10^7 S/m

E = ?

We will find R at first,

R = $l$/(A * б)

= $l$/$(2 * 10^-6 * 6.25 * 10^7)$

= $l$/(12.5 * 10)

=  $l$/125

Since V = iR = 1 *  $l$/125

= $\frac{l}{125}V$

E = dV/d$l$

E = 1/125 V/m

E = 1000/125

E = 0.008 V/m

∵ E = 8 mV/m

Learn more: Electric Field

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