Question

Calculate the electric field intensity 16 cm from a charge q=5nc

Answer 1

Answer:

The electric field intensity is 175$NC^-1$

Explanation:

Electric field intensity: The space around an electric charge in which its influence can be felt is known as the electric field. The electric field intensity at a point is the force experienced by a unit positive charge placed at that point. Electric Field Intensity is a vector quantity.

Find: The electric field intensity.

Using formula $E=\frac{1}{4\pi \varepsilon _O}\frac{q}{r^2}$

Here, q=$5\times 10^-6 c$

r=16 cm

So,

$E=9\times 10^9\times \frac{5\times 10^-6}{16\times 16}\\\\=\frac{45\times 10^3}{256}$

=$0.175\times10^3\\=175NC^-1$

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