Calculate the electric field strength required to just support a water drop of mass 10 to the power minus 3 kg and having a charge 1.6 into 10 to the power minus 19 c
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Calculate the electric field strength required just to support a water drop of mass 0.0000001 kg and having a charge of 1.6*10 to the power -19C
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Answer:
E= 6.12 × 10^-16 N/C
Explanation:
m= 10^-3 kg
e= 1.6×10^-19 C
g= 9.8 m/s^2
Let, E be the strength of the electric field required to just support the water drop.
Then,
Ee = mg
E = mg/e
E = 10^-3 × 9.8/1.6 × 10^-19
E = 6.12 × 10^-16 N/C.
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