Question

calculate the electric flux through a spherical surface of radius 10cm enclosing a negative charge of 8.853mc.
what happens to the flux when the radius of the surface is doubled?​

Answer 1

Answer:

since it doesnot depand on radius so no change in final answer

Formula

E= q/ €.

Answer 2

Concept:

The electric flux can be mathematically expressed as- Ф = q(enclosed)/ε₀

Given:

Radius of spherical surface = 10cm

Negative charge = 8.85mC = 8.85 × 10⁻³ C

Find:

We need to determine the electric flux through a spherical surface and know what happens to the flux when the radius of the surface is doubled.

Solution:

We have, Charge, q = 8.85mC which was converted to q = 8.85 × 10⁻³ C

We know, that flux can be calculated by the formula-

Ф = q(enclosed)/ε₀ where Ф is the electric flux, q is the charge and ε₀ is the dielectric permittivity of vacuum

We know, that ε₀ = 8.85 × 10⁻¹²

Therefore, the equation for electric flux becomes-

Ф = 8.85 × 10⁻³/8.85 × 10⁻¹²

Ф = 10⁹ Nm²/C

When the radius of the surface is doubled, no change in the electric flux will occur because the electric flux is not dependent on the radius, it depends on the charge of the surface.

Thus, the electric flux through a spherical surface is 10⁹ Nm²/C and no change in the electric flux will occur when the surface radius is doubled.

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