Question

calculate the electric force of a charge having magnitude 1.6 into 10 power minus 19 coulomb in a uniform electric field having magnitude is 6 into 10 is power 25 Newton per coulomb ​

Answer 1

Answer:

Explanation:FAB| = k (7 × 10-6)((2× 10-6) / (4 × 10-2)2 = 14 × 10-12 k / (16 × 10-4) = 0.875 k × 10-8

|FCB| = k (2× 10-6)(2× 10-6) / (2 × 10-2)2 = k × 10-8

We now use Pythagora's theorem to find the magnitude of the resultant force F = FAB + FCB (a vector sum)

|F| = √(|FAB|2 + |FCB|2) = k × 10-8 √( 0.875 2 + 12 ) = 9.00 × 109 × 10-8 √( 0.875 2 + 12 ) = 1.20 × 102 N

θ = arctan(|FCB|/ |FAB| ) = arctan( k × 10-8 / 0.875 k × 10-8) = 48.8°