Calculate the electrical energy consumed in juice. If a tester of 60 w is used for 30 min?
Answers
Answered by
1
p= 60 w
time= 30 m
=1/2 hr
electrical energy=
[tex] \frac{pt}{1000 } \\ \\ \frac{60*0.5}{1000} \\ \\ \frac{30}{1000} =0.03 kwh[/tex]
time= 30 m
=1/2 hr
electrical energy=
[tex] \frac{pt}{1000 } \\ \\ \frac{60*0.5}{1000} \\ \\ \frac{30}{1000} =0.03 kwh[/tex]
Answered by
1
Power of tester = 60W = 60J/s
time = 30m = 30×60 s = 1800s
Energy consumed = Pt = 60×1800 = 108000J = 108kJ
time = 30m = 30×60 s = 1800s
Energy consumed = Pt = 60×1800 = 108000J = 108kJ
Revolution:
both are correct..0.03 kwh=108 kj
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