Calculate the electrons's presenting numbers of 1 mole methen
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The number of electrons present in 1 molecule of methane is CH4 = 1(6) + 4(1) = 10 electrons. 1 molecule of methane has 10 electrons. 1 mole of methane has 6.023X10^23 molecules of methane. Number of electrons present in 1 molecule of methane = 10 Number of electrons present in 6.023X10^23 molecules of methane = 6.023X10^23 X 10 = 6.023X10^24 electrons
hope this helps you out!
hope this helps you out!
kadddu:
thank you dear
okk
can u Explain me how 1 mole pf CH4 has 6.023×1023 please....
ohhh okk thank you so much
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Hii There!!!
No. of electrons present in 1 mole of CH4
= 1(6) + 4(1) = 10 electrons
Since , 1 mole of CH4 has 6.023×10^23 molecules of CH4.
So, no. of molecules present in 1 mole of CH4 = 6.023×10^23 × 10
=> 6.023×10^24electrons
Therefore, electrons present in 1 mole of CH4 are 6.023 × 10^24 electrons.
_______________________
# ¢'$ #
Hope it helps :)
No. of electrons present in 1 mole of CH4
= 1(6) + 4(1) = 10 electrons
Since , 1 mole of CH4 has 6.023×10^23 molecules of CH4.
So, no. of molecules present in 1 mole of CH4 = 6.023×10^23 × 10
=> 6.023×10^24electrons
Therefore, electrons present in 1 mole of CH4 are 6.023 × 10^24 electrons.
_______________________
# ¢'$ #
Hope it helps :)
how 1 mole ch4 has 6.023×1020 moles pf ch4
Sorry by mistake I've written wrong.Now my ans. is edited..
okkkk
How 1 mole of Ch4 has 6.023×1023 please can u explain me
6.023×10^23 is Avogadro's no. which is same for every molecule.
Nicely Explained My Dear :K
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