Calculate the emf for the given cell at 25°c: cr/cr'3+(0,1M)//Fe'2+(0.01M)/Fe
Given : E°cr'3+/Cr=0.74, E°Fe'2+/Fe=-0.44V
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Explanation:
Ecell=Ecathode-Eanode
=-0.44+0.74
=0.30V
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