Question

Calculate the emf of the cell

Zn/Zn2+ (0.001M) // Cu2+ (0.1M)/Cu
The standard potential of Cu/ Cu2+ half cell is +0.34 and Zn/Zn2+ is - 0.76 v.​

Answer 1

Explanation:

Given Zn∣Zn2+(0.001M)∣∣Cu2+(0.1M)∣Cu

Overall cell reaction:

Zn⟶Zn2++2e−Cu2++2e−⟶CuZn+Cu2+⟶Zn2++Cu

Ecello=standard reduction potential of cathode + standard oxidation potential of anode

Ecello=0.34 to 0.76 V

Ecello=1.1 V

KC=[Cu2+][Zn2+]=10−110−3=10−2

EMF of the cell at any electrode concentration is:

E=Eo−n0.059log(KC)=1.1−20.059log(10−2)=1.1−2<

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