Calculate the emf of the cellat 25°C
Zn / Zn2+ (0.01M) 11 Ee27 (0.005M) / Fe
EO (Zn2+ / zn) = 0.763 V and EO (Fe2+/Fe)=. -0.440
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cell at O. 444000 o. e763h
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Answer is
............
0.314V
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