Calculate the empirical and molecular formula. A compound, X, contains 55.85% carbon, 6.97% hydrogen and 37.18% oxygen. (i) How does this prove that compound X contains only carbon, hydrogen and oxygen? (ii) Use the above percentages to calculate the empirical formula of compound X. (iii) The M, of X is 86. What is its molecular formula?
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Answer:
Explanation:
58.85 divide 12 6,97 divide 1 37,18 divide 16
4,9 6,97 2.32 /divide 2,32
2.11 3.00 1
C2H3O=12•2+1•3+16•1
=24+3+16
=43
Mr=86 divide 43
=2•C2H3O=
=86
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